(3n-6)/(n^2-4)

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Solution for (3n-6)/(n^2-4) equation: 


D( n )

n^2-4 = 0

n^2-4 = 0

n^2-4 = 0

1*n^2 = 4 // : 1

n^2 = 4

n^2 = 4 // ^ 1/2

abs(n) = 2

n = 2 or n = -2

n in (-oo:-2) U (-2:2) U (2:+oo)

(3*n-6)/(n^2-4) = 0

3*n-6 = 0 // + 6

3*n = 6 // : 3

n = 6/3

n = 2

n in { 2} 

n belongs to the empty set

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